Question 1064374
the sum of four consecutive even integers is 2 more than 
5 times the first integer. Find the smallest integer.
<pre><font size=4><b>

first (smallest) even integer = n
second even integer = n+2
third even integer = n+4
fourth even integer = n+6
</pre>
the sum of four consecutive even integers is 2 more than 
5 times the first integer.
<pre>
n+(n+2)+(n+4)+(n+6) = 5n+2

Find the smallest integer.

Solve for n.

Edwin</pre></font></b>