Question 1064366
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n = first integer
n+1 = second integer
n+2 = third integer
n+3 = fourth integer
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The sum of four consecutive positive integers is 'X"
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n+(n+1)+(n+2)+(n+3) = X
      n+n+1+n+2+n+3 = X
               4n+6 = X
                 4n = X-6
                  n = {{{(X-6)/4}}}

n+1 = second integer = {{{(X-6)/4+1 = (X-6)/4 + 4/4 = ((X-6)+4)/4 = (X-6+4)/4 = (X-2)/4}}} 
n+2 = third integer = {{{(X-6)/4+2 = (X-6)/4 + 8/4 = ((X-6)+8)/4 = (X-6+8)/4 = (X+2)/4}}}

What is the sum of the second and third integers?

{{{(X-2)/4+(X+2)/4=((X-2)+(X+2))/4=(X-2+X+2)/4=(2X)/4=X/2}}}

Edwin</pre></font></b>