Question 1064345
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Tickets at a basketball game were $4 for an adult and $2 for a student. The total number of tickets sold was 300. 
If the sales of tickets was $800, how many tickets of each were sold?

Thank you!
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Two ways to solve.


<U>Solution 1</U>.  Two equations


<pre>
 A +  S = 300,   (1)
4A + 2S = 800.   (2)   (the "value" equation)

Divide eq.(2) by 2 (both sides). Rewrite you system as

 A + S = 300,    (1')
2A + S = 400.    (2')

Distract eq.(2') from (1') (both sides). You will get

A = 100.

<U>Answer</U>. 100 adults tickets and 300-100 = 200 student tickets.
</pre>

<U>Solution 2</U>.  One equation


<pre>
Let "A" be the number of adults' tickets.
Then the number of students' tickets is 300-A.

The value equation is 

4A + 2*(300-A) = 800.

Simplify and solve for A.
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