Question 1064311
 prove that 16^4-2^13-4^5 is divisible by 11
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(2^4)^4 - 2^13 - (2^2)^5= 2
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2^16 - 2^13 - 2^10
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2^10[2^6 - 2^3 - 1]
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2^10[64-8-1]
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= 2^10[55]
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Since 55 is divisible by 11, the original number is
divisible by 11
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Cheers,
Stan H.
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