Question 1064263
Same as the focus of the parabola {{{y^2+4x+2y-8=0}}}.


{{{4x=-y^2-2y+8}}}
{{{4x=-1(y^2+2y-8)}}}
{{{4x=-1(y^2+2y+1-1-8)}}}
{{{4x=-1((x+1)^2-9)}}}, vertex is the right-most point and parabola opens toward the left.  Vertex is at  (-1,-9/4).



The focus is 1 unit to the left of vertex, so this focus is at  (-2,-9/4).