Question 1064208
{{{f(x)=-2(x^2+6x+5)}}}

The term to complete the square is 9.  Do this inside the parentheses.

{{{-2(x^2+6x+5)}}}
{{{-2(x^2+6x+9-9+5)}}}
{{{-2((x+3)^2-4)}}}
{{{cross(f(x)=-2(x+3)^2+2)}}}
{{{f(x)=-2(x+3)^2+8}}}
<s>Vertex is  (-3,2).</s>
Vertex is (-3,8).


Find x intercepts using  {{{cross(-2(x+3)^2+2=0)}}},{{{-2(x+3)^2+8=0}}};


Find any y intercepts by evaluating {{{f(0)}}}.



EDITED GRAPH;  FIXED ARITHMETIC MISTAKE
{{{graph(300,300,-6,6,-2,10,-2(x+3)^2+8)}}}