Question 1064212
graph 4x-x^2 and look for the part where f(x) > 0.
{{{graph(300,300,-5,5,-10,10,4x-x^2)}}}


4x-x^2 must be greater than 0. ln (0) does not exist, nor does ln of a negative number
Therefore, -x^2+4x=0
same as x^2-4x=0
x*(x-4)=0
x=0 (not allowed)
x=4 (not allowed)
Need to test x between 0 and 4.  Try 1,2,3
for 1, ln (3)
for 2, ln (4)
for 3, ln (3)
Try 5
ln (20-25) does not work.
Domain is 0 < x < 4
{{{graph(300,300,-3,5,-10,10,ln(4x-x^2))}}}