Question 1064160

The perimeter of a triangle is 44 cm. One of its sides is 4 cm smaller than the other and twice as long as the third side. Find the sides of the triangle?
<pre>Let the other (2nd) side be S
Then 1st side = S - 4
Also, 1st side is twice 3rd side, or 3rd side is {{{matrix(1,8, (1/2), of, 1^(st), side, or, (1/2) * (S - 4), or, (S - 4)/2)}}}
Since the sides sum to 44 cm, we get: {{{S + S - 4 + (S - 4)/2 = 44}}}
{{{2S - 4 + (S - 4)/2 = 44}}}
{{{2S + (S - 4)/2 = 48}}}
4S + S - 4 = 96 ------- Multiplying by LCD, 2
5S = 96 + 4
5S = 100
S, or {{{highlight_green(matrix(1,7, 2^(nd), side, "=", 100/5, or, 20, cm))}}} 
{{{highlight_green(matrix(2,7, 1^(st), side, "=", 20 - 4, or, 16, cm, 3^(rd), side, "=", (20 - 4)/2, or, 8, cm))}}}