Question 1064124
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For either of these:

{{{y = A*sin(B*x + C)+D}}} or {{{y = A*cos(B*x + C)+D}}}

{{{matrix(1,3,amplitude,""="",abs(A) )}}}
{{{matrix(1,3,period,""="",2pi/B )}}}
{{{matrix(1,4,phase,shift,""="",-C/B )}}}
{{{matrix(1,4,vertical,shift,""="",D )}}}

Your problem is this:

{{{y = 2sin(2x-pi)}}}

where

{{{matrix(1,7,A=2,",",B=2,",",C=-pi,",",D=0)}}}

Now you can finish by substituting.  If you have trouble
substituting, tell me about it in the thank-you note form 
below, and I'll get back to you by email.  No charge ever!

Edwin</pre></font>