Question 1064074

ΔABC has vertices at A(8,3), B(7,5), and C(2,4). Point D, located on AC¯ at approximately (6.7,3.22), is the intersection of the altitude drawn from B to AC¯.

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The area of △ABC is _____ units2.
<pre>Just calculate the length of AC, the base, using the distance formula: {{{d = sqrt((x[1] - x[2])^2 + (y[1] - y[2])^2)}}}, and the length of the altitude, or BD.
Now, take half the product of AC and BD, since the area of a triangle is calculated as {{{(1/2) * base * height}}}
That's all.......nothing too COMPLEX and/or CONFUSING.