Question 1064040
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A 30-60-90 right triangle with a long leg of 1 has hypotenuse of *[tex \Large \frac{2\sqrt{3}}{3}] and a short leg of *[tex \Large \frac{\sqrt{3}}{3}], so a similar triangle with dimensions 9 times as long would have a long leg of 9, a hypotenuse of *[tex \Large 6\sqrt{3}], and a short leg of *[tex \Large 3\sqrt{3}].  Calculate the area of the larger triangle and then consider that the hexagon is made up of 12 such triangles.


Note:  Since the answer will come out as an even integer but you are asked for the answer to the nearest tenth, be sure to include .0 on the end of your answer.  For example, if your calculation comes out to be 100 (it won't), then your answer would be 100.0


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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