Question 1064036
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The point given is in the form *[tex \Large \left(x,\,f(x)\right)].  Meaning that the value *[tex \Large x] pairs with the value *[tex \Large f(x)], and the value *[tex \Large f(x)] is the calculated value of the function when *[tex \Large x] is the given value.  What you are being asked is does *[tex \Large f(-1)\ =\ -3]?


So, write *[tex \Large f(x)\ =\ -3x^2\ -\ 6x\ -\ 6] in pencil.  Erase every instance of *[tex \Large x] and replace it with *[tex \Large (-1)].  Then do the indicated arithmetic.  If the result is *[tex \Large -3], then the given point is, indeed, on the graph.  Otherwise not.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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