Question 1064007
{{{abs((x+2)/4)>=3}}}


{{{(1/4)abs(x+2)>=3}}}


{{{abs(x+2)>=4*3}}}


{{{abs(x+2)>=12}}}



Solve for two possibilities from here.
{{{system(x+2>=0,x+2<0)}}}



If non-negative:
then
{{{x+2>=12}}}
-
If negative
then
{{{-(x+2)>=12}}}
-
Solve each of them.  Make the necessary conclusion.