Question 13436
{{{I = nE/(nr+R)}}}


First of all congratulations for writing the equation in correct algebra.com format!!


Next, let's clear the fraction by multiplying both sides of the equation by (nr+R):

{{{I = nE/(nr+R)}}}
{{{I*(nr+R)  = (nE/(nr+R)) * (nr+R)}}}


The (nr+R) divides out on the right side:
{{{I(nr+R) = nE}}}
{{{Inr +IR = nE}}}  


Get all the n terms to the right side by subtracting Inr from each side:

{{{Inr - Inr  +IR = nE-Inr }}}


Factor out the n to get the n in one place:
{{{IR = n(E-Ir) }}}


Divide both sides by (E-Ir):
{{{(IR)/(E-Ir) = (n(E-Ir))/(E-Ir) }}}


{{{(IR)/(E-Ir) = n }}}


R^2 at SCC