Question 1063893
<pre>
              SPEED     TIME      DISTANCE
WALK           2         t         d
JOG            6        t-1/4      d
</pre>


The question asks for d.


{{{2t=d}}}
{{{t=d/2}}}
-
{{{6(t-1/4)=d}}}
{{{6(d/2-1/4)=d}}}
{{{3d-3/2=d}}}
{{{cross(d-3/2=0)}}}------------------arithmetic mistake
{{{highlight(cross(d=3/2=1&1/2))}}}
should be as
{{{2d-3/2=0}}}

{{{2d=3/2}}}

{{{d=3/(2*2)}}}

{{{highlight(d=3/4)}}}