Question 1063625
<pre>
{{{matrix(1,3,"g(x)",""="",2cos^""(3x-2)+5)}}}

We can see why if we factor out 3 within what the 
cosine is being taken of:

{{{matrix(1,3,"g(x)",""="",2cos^""(3(x-2/3)^"")+5)}}}

The phase shift is determined by what has been added to or 
subtracted from the variable x, NOT 3x.  Only by factoring 
out the coefficient of x (when it isn't 1), can we see in 
the equation what is added to or subtracted from x.

The actual phase shift is {{{2/3}}} radians to the right.

Edwin</pre>