Question 1063620
Q: Three numbers are in ratio 2:3:4 and the sum of their squares is 725.find the numbers 

Tutorial:
The numbers are 2k, 3k, and 4k for some positive constant k.
The sum of their squares is equal to
{{{(2k)^2 + (3k)^2 + (4k)^2 = 725}}}
{{{4k^2 + 9k^2 + 16k^2 = 725}}}
{{{29k^2 = 725}}}
Divide both sides by 29
{{{k^2 = 725/29}}}
{{{k^2 = 25}}}
Get the positive square root of both sides.
k = 5
So 2k = 10, 3k = 15, and 4k = 20.
The numbers are {{{highlight(10)}}}, {{{highlight(15)}}}, and {{{highlight(20)}}}