Question 1063601
 Use 3x^2 +3x =21 and use the discriminant to find the number of unique real solutions. Show all calculations.

  Thanks very much.
<pre>{{{matrix(1,5, 3x^2 + 3x = 21, "=====>", 3x^2 + 3x - 21, "=", 0)}}}
Using the discriminant: {{{b^2 - 4ac}}}, we get: {{{matrix(1,5, 1^2 - 4(1)(- 7), "=", 1 + 28, "=", 29)}}}
With the discriminant being 29, and part of the solution being: {{{sqrt(29)}}}, it follows that there are: {{{highlight_green(matrix(1,6, 2, "REAL,", UNEQUAL, and, IRRATIONAL, solutions))}}}