Question 1063585
 Given the equation x+4y^2 =16 
a) find the intercepts
If x = 0, y = +2 or x = -2
y-int's:: (0,2) and (0,-2)
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If y = 0, x = 16
x-int:: (16,0)
B)Is the graph symmetric with the x or y axis or both. What are the features that determine the symmetries.
f(x) = +-sqrt[16-x]
f(-x) = +-sqrt[16+x]
-f(-x) = +-sqrt[16+x]
Since f(-x) = -f(-x) you have origin symmetry
Since f(x) # -f(x) you do not have y-axis symmetry
It appears there is x-axis symmetry.
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Graph::
{{{graph(400,400,-10,20,-10,10,sqrt(16-x),-sqrt(16-x))}}}
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C) Graph the Equation. Find three additional points besides the intercepts.
I'll leave that to you.
Cheers,
Stan H.
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