Question 1063580
.
Find all solutions to the equation.
=2cosθ-√3=0
Write your answer in radians in terms of π
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


<pre>
{{{2*cos(theta)}}} - {{{sqrt(3)}}} = 0  --->  {{{2*cos(theta)}}} = {{{sqrt(3)}}}  --->  {{{cos(theta)}}} = {{{sqrt(3)/2}}} --->  


There are TWO families of solutions:


{{{theta}}} = {{{pi/6 + 2k*pi}}},  k = 0, +/-1, +/-2, . . .   AND/OR  


{{{theta}}} = {{{11pi/6 + 2k*pi}}},  k = 0, +/-1, +/-2, . . .   .
</pre>

To see more examples of solved trigonometry equations with detailed solutions, look into the lessons 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Trigonometry-basics/Solving-simple-problems-on-trigonometric-equations.lesson>Solving simple problems on trigonometric equations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Trigonometry-basics/Solving-typical-problems-on-trigonometric-equations.lesson>Solving typical problems on trigonometric equations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Trigonometry-basics/Solving-more-complicated-problems-on-trigonometric-equations.lesson>Solving more complicated problems on trigonometric equations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Trigonometry-basics/Solved-problems-on-trigonometric-equations.lesson>Solving advanced problems on trigonometric equations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Trigonometry-basics/OVERVIEW-of-lessons-on-calculating-trig-functions-and-solving-trig-equations.lesson>OVERVIEW of lessons on calculating trig functions and solving trig equations</A>

in this site.



Also, you have this free of charge online textbook in ALGEBRA-II in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-II - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this online textbook under the topic "<U>Trigonometry: Solved problems</U>".