Question 93236
If:
{{{f(x) = -x^2-3x+5}}} and
{{{g(x) = (x+3)/(2x-5)}}}
Find:
{{{g(f(2))}}}
First find {{{f(2)}}} by substituting 2 for x in the function{{{f(x) = -x^2-3x+5}}}
{{{f(2) = -(2)^2-3(2)+5}}} Evaluate this.
{{{f(2) = -4-6+5}}}
{{{f(2) = -5}}} Now substitute -5 for x in the function{{{g(x) = (x+3)/(2x-5)}}}
{{{g(-5) = (-5+3)/(2(-5)-5)}}}
{{{g(-5) = (-2)/(-15)}}}
{{{g(-5) = 2/15}}}
So, {{{g(f(2)) = 2/15}}}