Question 1063512
<pre><b>4 Aces CHOOSE 2 = 4C2 = (4&#8729;3)/(2&#8729;1) = 12/2 = 6 ways

times:

4 Jacks CHOOSE 3 = 4C3 = (4&#8729;3&#8729;2)/(3&#8729;2&#8729;1) = 24/6 = 4 ways

That's 6×4 = 24 successful ways

52 Cards CHOOSE 5 = (52&#8729;51&#8729;50&#8729;49&#8729;48)/(5&#8729;4&#8729;3&#8729;2&#8729;1) = 311875200/120 =

2598960 possible ways.

Probability = 24 successful ways out of 2598960 possible ways = 
24/2598960 = 1/108290

Edwin</pre></b>