Question 1063427
The sum of digits
B+E+N+J+A+M+I
contains all the digits listed, so it is
1+2+3+4+5+6+7=28
The sum of all digits is
28+N , and it must be a multiple of 3,
because the number BENJAMIN is a multiple of 3.
The only possibilities are
28+2=30 and 28+5=33 , so N=2 or N=5.
N, the last digit in BENJAMIN, must be odd,
because BENJAMIN is an odd number.
So, N=5.