Question 1063402
Newgy has twice as many nickels as dimes,and four times as many pennies as nickels. If she has a total of $2.80, how many of each coin does she have?
<pre>Let number of dimes be D
Then number of nickels = 2D
Number of pennies = 4(2D), or 8D
We then get: .1D + .05(2D) + .01(8D) = 2.8
.1D + .1D + .08D = 2.8
.28D = 2.8
D, or number of dimes = {{{highlight_green(matrix(1,3, 2.8/.28, or, 10))}}}
Number of nickels: {{{highlight_green(matrix(1,3, 2(10), or, 20))}}}
Number of pennies: {{{highlight_green(matrix(1,3, 8(10), or, 80))}}}
It's as easy as that....nothing COMPLEX and/or CONFUSING!