Question 1063374
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I need to solve this equation for the interval [0, 2pi) :
-tan^2(x)+3 = 2tanx+4
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<pre>
{{{-tan^2(x)+3}}} = 2tanx + 4   --->  

{{{tan^2(x) + 2tan(x) + 1}}} = 0  --->

{{{(tan(x) + 1)^2}}} = 0  --->

tan(x) + 1 = 0  --->  tan(x) = -1   --->  x = {{{3pi/4}}}  and/or  x = {{{7pi/4}}}.

<U>Answer</U>.  There are two solutions  x = {{{3pi/4}}}  and/or  x = {{{7pi/4}}}.
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