Question 1063322
Your equation is in the point-slope form and shows you the slope is 2 and that one of the points on the line is (-3,1).  You are also given a point  (1,0), meaning that  (not clear from the description) it too is on the line.


Is the given point  (1,0) on the line?
{{{y-1=2(x+3)}}}
{{{0-1=2(1+3)}}}
{{{-1=8}}}----FALSE.


What do you really want with this exercise?  



The equation's known point (-3,1) and slope 2 give you enough to graph the line given:
{{{graph(300,300,-6,4,-2,8,2(x+3)+1)}}}