Question 93210
{{{L=(3/4)F+8}}} Start with the given equation



{{{10=(3/4)F+8}}} Plug in L=10



{{{(4)(10)=(4)((3/4)F+8)}}} Multiply both sides by the LCM of 4. This will eliminate the fractions  (note: if you need help with finding the LCM, check out this <a href=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>)




{{{40=3F+32}}} Distribute and multiply 4 by each term on both sides



{{{0=3F+32-40}}} Subtract 40 from both sides



{{{-3F=32-40}}} Subtract 3F from both sides





{{{-3 F=-8}}} Combine like terms -40 and 32 on the right side to get -8






{{{F=(-8)/(-3)}}} Now divide both sides by  -3 to isolate and solve for F



{{{F= 8 / 3}}} Reduce




So the approximate answer is


{{{F=2.66666666666667}}}


which rounds to


{{{F=2.667}}}


So the force needed is about {{{F=2.667}}}