Question 1063275
The assumption is that 2 students in the front seat and 3 students in the back seat is modeled by "arranging 5 students in 5 chairs"
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(1)  Since order is not important, then we have
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5! = 120 ways
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(2)  There are 3 possibilities for the driver's seat
3C1 = 3! / (1! * (3-1)!) = 3
so we multiply 3 times 4! = 72

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There are 72 ways if only 3 of the 5 can drive and others cannot
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