Question 1063261
{{{x^2+6x-7=0}}}
{{{(x+7)(x-1)=0}}}
x-intercepts are -7, and +1.


The value in the exact middle of these intercepts and on the x-axis is  {{{(-7+1)/2=-3}}}.


Vertex will be at {{{system(x=-3,y=(-3)^2+6(-3)-7=9-18-7=-16)}}}, or the point (-3,-16).