Question 1063231
<pre>
If 2^x=5, then 5^x = ?

{{{2^x}}}{{{""=""}}}{{{5}}}

{{{log2^x)}}}{{{""=""}}}{{{log5}}}

{{{x*log2}}}{{{""=""}}}{{{log5}}}

{{{x}}}{{{""=""}}}{{{log5/log2}}}{{{""=""}}}{{{2.321928095}}}

Raise 5 to the power of each side:

{{{5^x}}}{{{""=""}}}{{{5^2.321928095}}}

{{{5^x}}}{{{""=""}}}{{{49.97184792}}}

Edwin</pre>