Question 1063131
p(S) unknown
p(J)=0.8
p(J)*p(S)=0.6, because independent.
Therefore, p(S)=0.75
Probability that only one will qualify is P(J)*p(NS)=0.8*0.25=0.2+
p(NJ)(p(S)=0.2*0.75=0.15
They add to 0.35