Question 13429
You first need to name the three consecutive even integers using the name variable. I am going to call them n, n+2, and n+4 (we are doing +2 and +4 because even numbers are two apart...think about 2, 4, and 6 for example).  When you add these together and set it equal to twice the smallest, you get the equation {{{n+n+2+n+4 = 2n}}}.  To solve, first combine like terms to get {{{3n+6 = 2n}}}.  Move the 3n to the right side of the equal sign to get {{{6 = -1n}}}.  Divide by -1 to solve for n to get {{{n = -6}}}.  Your three consecutive even integers are -6, -4, and -2.