Question 1063061
{{{A=1+B}}}
So,
{{{A^2=(1+B)^2}}}
{{{A^2=1+2B+B^2}}}
and
{{{2(1+2B+B^2)+20=B^3}}}
{{{B^3-2B^2-4B-22=0}}}
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Graph the B function to find where it has a zero.
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*[illustration AD2.JPG].
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{{{B=4.2}}}
so then,
{{{A-4.2=1}}}
{{{A=5.2}}}