<PRE><B>Question 1062972</B>
A log measuring 3M 68cm long was cut into 3 parts: A, B, and C. Part A is 75cm longer than Part B, but 50cm shorter than Part C. Find the length of Part C. 
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A = B + 75 cm
A = C - 50 cm
A + B + C = 368 cm
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Substitute and solve for &quot;A&quot;
A + (A-75) + (A+50) = 368
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3A - 25 = 368
3A = 393
A = 131 cm
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Ans: C = A + 50 = 181 cm = 1m 81cm
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Cheers,
Stan H.
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