Question 1062934
Note the general formula for householder is H = I(n) - 2WW^T/((W^T)W) = I(n) + beta(WW^T)
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(a) H is symmetric then we need to show H^T = H
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H = I(n) - 2WW^T
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H^T = (I(n) -2WW^T)^T = I(n)^T -2(WW^T)^T = I(n) -2(W^T)^TW^T = I -2WW^T = H 
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I used the basic properties of a transposed matrix
(1) for alpha a scaler (aA)^T = aA^T
(2) (A+B)^T = A^T + B^T
(3) (AB)^T = (B^T)A^T
(4) (A^T)^T = A
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(b) show H^(-1) = H^T
from definition HH^(-1) = H^(-1)H = I(n)
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H is orthogonal, namely H(H^T) = I(n), since H is symmetric (H^T)H = I(n) 
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To show H is orthogonal multiply (I(n) - 2WW^T) by itself and factor it out
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