Question 1062936
{{{100=200e^(k(1/2))}}}
{{{e^(k/2)=1/2}}}
{{{k/2=1n(1/2)}}}
{{{k=2*ln(1/2)}}}
{{{k=-2*ln(2)}}}
So then,
{{{3.125=200e^(kt)}}}
{{{e^(kt)=3.125/200}}}
{{{kt=ln(1/64)}}}
{{{kt=-ln(64)}}}
{{{t=-ln(64)/(-2ln(2))}}}
{{{t=-ln(2^6)/(-2ln(2^1))}}}
{{{t=6/2))}}}
{{{t=3}}}{{{hrs}}}