Question 1062921
{{{ 5*(pi/6) = pi - pi/6 }}}
This is an angle in the 2nd quadrant that
makes an angle of {{{ pi/6 }}} with horizontal axis
{{{ cos( pi/6 ) = sqrt(3)/2 }}}
{{{ sin( pi/6 ) = 1/2 }}}
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In the 2nd quadrant, the terminal point would be:
( -sqrt(3)/2, 1/2 )
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check:
{{{ 1^2 = ( -sqrt(3)/2 )^2 + (1/2)^2 }}}
{{{ 1 = .75 + .25 }}}
{{{ 1= 1 }}}
OK