Question 1062882
<pre><b><font size=4>

{{{system(4y=x+4,
x=expr(2/3)y+8/3)}}}

Get a table of values for the first equation:

{{{4y=x+4}}}     {{{4y=x+4}}}      {{{4y=x+4}}}
Let x=0     Let y=0     Let y=-1 
{{{4y=0+4}}}     {{{4(0)=x+4}}}    {{{4(-1)=x+4}}}
{{{4y=4}}}       {{{0=x+4}}}       {{{-4=x+4}}}
{{{y=1}}}        {{{-4=x}}}        {{{-8=x}}}
point (0,1)      point (-4,0)      point (-8,-1) 

Plot those three points and draw a line through them

{{{drawing(400,400,-10,10,-10,10,
circle(0,1,.15),circle(-4,0,.15), circle(-8,-1,.15),
circle(0,1,.1),circle(-4,0,.1), circle(-8,-1,.1),
circle(0,1,.2),circle(-4,0,.2), circle(-8,-1,.2),
graph(400,400,-10,10,-10,10,(x+4)/4))}}}

The other equation contains fractions, so it will be
easier if we first multiply every term in it through by the
LCD of 3:

{{{x=expr(2/3)y+8/3)}}}
{{{3x=2y+8}}}


{{{3x=2y+8}}}     {{{3x=2y+8}}}     {{{3x=2y+8}}}
Let x=0     Let y=-1     Let x=-2
{{{3(0)=2y+8}}}   {{{3x=2(-1)+8}}}  {{{3(-2)=2y+8}}}
{{{0=2y+8}}}      {{{3x=-2+8}}}     {{{-6=2y+8}}}
{{{-8=2y}}}       {{{3x=6}}}        {{{-14=2y}}}
{{{-4=y}}}        {{{x=2}}}         {{{-7=y}}}
point (0,-4)      point (2,-1)      point (-2,-7) 

{{{drawing(400,400,-10,10,-10,10,
circle(0,1,.15),circle(-4,0,.15), circle(-8,-1,.15),
circle(0,1,.1),circle(-4,0,.1), circle(-8,-1,.1),
circle(0,1,.2),circle(-4,0,.2), circle(-8,-1,.2),

circle(0,-4,.15),circle(2,-1,.15), circle(-2,-7,.15),
circle(0,-4,.1),circle(2,-1,.1), circle(-2,-7,.1),
circle(0,-4,.2),circle(2,-1,.2), circle(-2,-7,.2),

graph(400,400,-10,10,-10,10,(x+4)/4,(3/2)x-4))}}}

Now notice the point where the two lines cross. From
that point draw a vertical line directly down to the 
x-axis, and a horizontal line over to the y-axis like 
this:

{{{drawing(400,400,-10,10,-10,10,
circle(0,1,.15),circle(-4,0,.15), circle(-8,-1,.15),
circle(0,1,.1),circle(-4,0,.1), circle(-8,-1,.1),
circle(0,1,.2),circle(-4,0,.2), circle(-8,-1,.2),

circle(0,-4,.15),circle(2,-1,.15), circle(-2,-7,.15),
circle(0,-4,.1),circle(2,-1,.1), circle(-2,-7,.1),
circle(0,-4,.2),circle(2,-1,.2), circle(-2,-7,.2),

triangle(4,2,4,0,4,1), triangle(0,2,2,2,4,2),


graph(400,400,-10,10,-10,10,(x+4)/4,(3/2)x-4))}}}

We see that the vertical line hits the x-axis at 4.
That means x=4 is the answer for x.

We see that the horizontal line hits the y-axis at 2.
That means y=2 is the answer for y.

Solution:  x=4, y=2.

Edwin</pre></font></b>