Question 1062873
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  xy\ =\ 88]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x\ +\ y\ =\ 26]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  y\ =\ 26\ -\ x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x(26\ -\ x)\ =\ 88]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x^2\ -\ 26x\ +\ 88\ =\ 0]


Solve the quadratic equation. The pair of solutions will be the desired numbers.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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