Question 1062863
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find the inverse of 5log(3x+7/4x-9) ?
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<pre>
The additive inverse is  {{{-5log(((3x+7)/(4x-9)))}}},  or (which is the same)   {{{5log(((4x-9)/(3x+7)))}}}


The multiplicative inverse is  {{{1/(5log(((3x+7)/(4x-9))))}}}.
</pre>