Question 1062776
f(x) = (x-2)^2 + 4
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f(x) = x^2 -2x +4 +4
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f(x) = x^2 -2x +8
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this is a parabola the curves upward
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the minimum value of f(x) occurs when x is the coordinate of the parabola's vertex
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x = -b/2a = -(-2) / (2*(1)) = 2 / 2 = 1
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the minimum value for f(x) occurs at x = 1
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here is a graph of f(x)
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{{{ graph( 300, 200, -5, 5, -2, 25, x^2 -2x +8) }}}
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