Question 93122
1) Solve using the quadratic formula:{{{x = (-b+-sqrt(b^2-4ac))/2a}}}
{{{3x^2 = 11x+4}}}
First, write the equation in standard form for quadratic equations:
 {{{ax^2+bx+c = 0}}}
{{{3x^2-11x-4 = 0}}} Here, you can see that: a = 3, b = -11, and c = -4
Make the appropriate substitutions into the formula and solve for x:
{{{x = (-(-11)+-sqrt((-11)^2-4(3)(-4)))/2(3)}}} Simplify this.
{{{x = (11+-sqrt(121-(-48)))/6}}}
{{{x = (11+-sqrt(169))/6}}}
{{{x = (11+13)/6}}} or {{{x = (11-13)/6}}}
{{{x = 24/6}}} or {{{x = -2/6}}}
{{{x = 4}}} or {{{x = -1/3}}}

2) Find the axis of symmetry for:
{{{y = -x^2+4x+2}}}
The axis of symmetry is given by:
{{{x = (-b)/4a}}}
Your equation here is already in standard form:{{{y = ax^2+bx+c}}} so a = -1, b = 4, and c = 2 
The axis of symmetry is:
{{{x = (-4)/2(-1)}}}
{{{x = (-4)/(-2)}}}
{{{x = 2}}} This is the equation of axis of symmetry!