Question 1062701
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log2x/ logx= 2  the correct working out to solve
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{{{log((2x))/logx}}} =  2  --->

log(2x) = 2*log(x)  --->  log(2x) = log(x^2)  --->  2x = x^2  --->  x^2 - 2x = 0  --->  x(x-2) = 0  ---> 

the unique appropriate solution is x = 2.

(x = 0 doesn't work).

<U>Answer</U>. The solution is x = 2
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