Question 1062688
The height cuts the isosceles triangle into two congruent right triangles, and twice the base of either of these is the base of the original isosceles triangle.


{{{b^2+15^2=25^2}}}


{{{b=sqrt(25^2-15^2)}}}


{{{b=20}}}


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Base is therefore  {{{2*20=40}}}.


AREA:  {{{(1/2)40*15}}}
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