Question 1062681
Let n be nickels, and p be pennies.  Then dimes are 2n, and quarters are 3(2n), or 6n. So:
p+n+2n+6n=p+9n=59
p+5n+10(2n)+25(6n)=p+175n=723
p+175n=723
p+9n=59
166n=664
n=4
2n=8
6n=24
p=23
You have 23  pennies, 4 nickels, 8 dimes, and 24 quarters. ☺☺☺☺