Question 1062675
Any line perpendicular to the line
{{{ y = (4/3)*x - 2 }}} will have slope 
{{{ m = -1/(4/3) }}}
{{{ m = -3/4 }}}
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(4,4)
The general form for a straight line is:
{{{ y = m*x + b }}}
so far I have:
{{{ y = (-3/4)*x + b }}}
plug in the given point
{{{ 4 = (-3/4)*4 + b }}}
{{{ 4 = -3 + b }}}
{{{ b = 7 }}}
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The equation is:
{{{ y = (-3/4)*x + 7 }}}
check my math!
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Here's the graph of the 2 equations:

{{{ graph( 400, 400, -10, 10, -10, 10, (-3/4)*x + 7, (4/3)*x - 2 ) }}}