Question 93116
How do i evaluate the following?
Comment: log is just another name for "exponent" or "power"
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log3 81
Let the answer be "x"
Then x= log3 81
So x is the exponent of 3 that gives you 81
3^x = 81
3^x = 3^4
x=4
log3 81 = 4

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log4 256
Similarly 
x = log4 256
4^x = 256
4^x = 4^4
x = 4
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log2 (1/32)
2^x = (1/32)
2^x = 2^-5
x = -5
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log5 1
5^x = 1
5^x = 5^0
x=0
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log3 (-1)
3^x = -1
No such x exists.
No solution.
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Cheers,
Stan H. 
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