Question 1062527
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In 10 years A will be twice as old as B was 10 years ago. If A is now 9 years older than B then the present age of B is?
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<pre>
The condition says:

A + 10 = 2*(B-10),     (1)    ("In 10 years A will be twice as old as B was 10 years ago.")
A = B + 9.             (2)    (" A is now 9 years older than B:)

From (2), substitute the expression A = B + 9 into (1), replacing A. You will get

(B+9) + 10 = 2(B-10),

B + 19 = 2B - 20  --->  19 + 20 = B.

Hence, B is 39 years old now.

Then A = B + 9 = 39 + 9 = 48 years old now.
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Solved.



There is a bunch of lessons on age word problems 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Age-problems-and-their-solutions.lesson>Age problems and their solutions</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Fresh-formulation-of-a-traditional-age-problem.lesson>A fresh formulation of a traditional age problem</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Really-intricate-age-word-problem.lesson>Really intricate age word problem</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/age/Selected-age-word-problems-from-the-archive.lesson>Selected age word problems from the archive</A>

in this site.


Read them and become an expert in solving age problems.


Also, you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this online textbook under the topic "<U>Age word problems</U>".