Question 1062497
25^y + 3 (5^y) =3
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{{{5^(2y) + 3*(5^y) - 3 = 0}}}
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Sub x for 5^y
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{{{x^2 + 3x - 3 = 0}}}
*[invoke solve_quadratic_equation 1,3,-3]
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Ignore the negative value
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x =~ 0.79129
5^y = 0.79129
y*log(5) = log(0.79129)
y = log(0.79129)/log(5)
y =~ -0.14545