<PRE><B>Question 1062427</B>
AE^2 = AF^2 + EF^2
:
AF = (1/2) * length of diagonal = (1/2) * (4 * square root(2)) = 2 * square root(2)
:
tangent(22.5) = EF / (2 * square root(2)) 
:
EF = (0.414) * (2 * square root(2)) = 0.828 * square root(2)
:
Note that tangent(22.5) = 0.414
:
AE^2 = (2 * square root(2))^2 + (0.828 * square root (2))^2 = 9.37
:
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AE = 3.06 cm
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